Problema. 6.

MOTOR 1(10HP, COS∅=0.88)

P=I N 1KVCos∅ n

IN 1=10∗746

√3∗220∗0.88∗0.9=24.72 A

ID1=I N 1∗1.25 ID1=24.72(1.25)

ID1=30.9 A

MOTOR 1(15HP, COS∅=0.85)

IN 2=15∗746

√3∗220∗0.85∗0.92=37.56 A

ID2=I N 2∗1.25 ID 2=37.56(1.25)

ID2=46.95 A

IN 2> IN 1

ID=1.25 I N 2+ IN 1

ID=1.25(37.56)+24.72

ID=71.67 A

Por tabla de cables: TW-80ID=88 A

S=K v∗L∗∑ I D∗cos∅

U∗U%

S=0.0309∗80∗[30.9∗0.88+46.95∗0.85 ]0.025∗220

S=30.16mm2

De tablas IDT=88 AS=30.16mm2

Stablas<Scable

16mm2<30.16mm2

De tabla concluimos:

IDT=110 AS=35mm2

I T=3∗110 A Sc=30.16mm2