2013_Ch.13_Notes-2
Transcript of 2013_Ch.13_Notes-2
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QMDS 202 Data Analysis and Modeling
Chapter 13 Inference About Comparing Two Populations
Dependent Versus Independent Samples
When making comparisons between the means of two populations, we need to pay particular attention to how we intend to collect sample data.
1. If there is a definite reason for pairing (matching corresponding data !alues, thetwo samples are dependent samples.
". If the two samples were obtained independently and there is no reason for pairing thedata !alues, the resulting samples are independent samples.
Inference #bout $he Difference %etween $wo &eans' Independent Samples
When the populations are normally distributed or the sies of two independent samples
are large (both n1 and n" are greater than or e)ual to *+, the sample statistic "1 X X − is a
normal random !ariable with mean ( )"1 µ µ − and !ariance
+
"
"
"
1
"
1
nn
σ σ
. $he confidence
inter!al of ( µ 1 µ " is found by'
( ) ( ) ( )"
""
1
"1
"-"1"1"
""
1
"1
"-"1nn
z x xnn
z x x σ σ µ µ
σ σ
α α ++−≤−≤+−−
If σ1 and σ" are unknown but equal, the confidence inter!al of ( µ 1 µ " is found by'
( ) ( ) ( )
++−≤−≤
+−−
"1
""-"1"1
"1
""-"1
1111
nn st x x
nn st x x p p α α µ µ
where "-α t is a score obtained from the t distribution with v n1 / n" 0 " and
"
1(1(
"1
"""1
"1"
−+−+−
=nn
n sn s s p pooled sample variance.
If σ1 and σ" are unknown and unequal, the confidence inter!al of ( µ 1 µ " is found by'
( ) ( ) ( )"
""
1
"1
"-"1"1"
""
1
"1
"-"1n
s
n
st x x
n
s
n
st x x ++−≤−≤+−− α α µ µ
where "-α t is a score obtained from the t distribution with v
( )( ) ( )
−+
−
+
1
-
1
-
--
"
"
"""
1
"
1"1
"
"""1
"1
n
n s
n
n s
n sn s
1
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ound the result of the calculation of v to the nearest integer.
23ample 1 # corporation owns two outlets # and %. # random sample of *4 days atoutlet # had a mean of 15+ sales daily. # random sample of *4 days at
outlet % had a mean sales of 146. #ssuming σ#" *4 and σ%
" "6, can we
conclude that there are more sales in outlet # at +.+6 le!el of significance7
Solution' 8+' µ1 ≤ µ" ⇔ µ1 −µ" ≤ + ( D+ the claimed !alue of µ1 −µ" stated in 8+ +81' µ1 > µ" ⇔ µ1 − µ" > +
α +.+6
%oth sample sies are large ⇒ "1 X X − is a normal random !ariable.Independent samples, σ1 and σ" are known ⇒ distribution will be used as the testing
distribution.
e9ect 8+ if $S : 1.4;6.
( )
"
""
1
"1
+"1
nn
D x xTS
σ σ +
−−= ( )
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Independent samples, σ1 and σ" are unknown and une)ual⇒ tdistribution will be used as
the testing distribution.
1*?".1"
11"
1"*"
11+
1+4"
1"
*"
1+
4"
11
""
""
""
"
"
"
""
1
"
1
"1
"
"
""
1
"1
==
−
+−
+
=
−
+−
+
=
n
n s
n
n s
n
s
n
s
v
e9ect 8+ if $S A ".14 or $S : ".14.
( )
"
""
1
"1
+"1
n
s
n
s
D x xTS
+
−−= ( ) 4?".+
1"
*"(
1+
4"(
+6
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Cote. We will use the e)ual!ariances test statistic and confidence inter!al estimator unless there is e!idence (based on the sample !ariances to indicate that the population!ariances are une)ual, in which case we will apply the une)ual!ariances test statistic andconfidence inter!al estimator.
Inference #bout $he Difference %etween $wo &eans' &atched @airs 23periment
When the populations are normally distributed and dependent samples (matched data are
obtained, the confidence inter!al of ( µ 1 µ " is found by'
( ) D
D D
D
D D
n
st x
n
st x "-"1"- α α µ µ +≤−≤−
23ample ; #n industrial engineer is e!aluating a new techni)ue to assemble air compressors. # sample of < employees is selected at random, and thenumber of compressors they each produce in one week using the e3isting procedure is recorded. $he same < workers are then trained to use the newtechni)ue and their output for one week is then noted. =onduct a test to
determine whether there is a difference between the two techni)ues with α
+.+6.
Employee A B C D E F G H
Old Method
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2 5;
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to be 1".
v1 n1 0 1 v" n" 0 1
e9ect 8+ if $S : "1 ,, vv F
α
""
"1 - s sTS =
Suppose' 8+'""
"1 σ σ ≥
81'""
"1 σ σ <
v1 n1 0 1 v" n" 0 1
e9ect 8+ if $S A "1,,1 vv F α −
"""1 - s sTS =
If independent samples are obtained from two normal populations, the confidence
inter!al of """1 -σ σ can be found by'
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1""1 ,,"-
""
"1
""
"1
,,"-
""
"1
-1
--
vvvv F
s s
F
s s
α α σ
σ ≤≤
In 23ample 6, the ?6B confidence inter!al of """1 -σ σ is'
?4."-1
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+6.+"++
6.+6.+
"++
;.+4.+I1(II1(II
"
""
1
11II "1
=×+×=−
+−
=−n
p p
n
p p p pσ
$he ?6B confidence inter!al of ( p1 0 p" is'
( ) +6.+?4.11.++6.+?4.11.+ "1 ×+≤−≤×− p p1?
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( )
"
""
1
11
"1
I1(II1(I
II
n
p p
n
p p
D p pTS
−+
−
−−=
e!iew @roblems' 1*.4, 1*.5, 1*.< a to c, 1*.1", 1*.6", 1*.64, 1*.54, 1*.