2gld sistemas vibratorios
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Transcript of 2gld sistemas vibratorios
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m1ẍ + (K 1 + k2)x1 − k2x2 = 0m2ẍ + (K 2 + k3)x2 − k2x1 = 0
X 1(t) = X 1cos(wt + φ1)
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X 2(t) = X 2cos(wt + φ2)
M Ẍ + KX = 0
m1 00 m2
ẍ1ẍ2
1 + k2 2
2 2 + k3
x1x2
00
|−Mw2 +k|
1 + k2 − m1w
2 2
2 2 + k3 − m2w2 m1m2w
4 − w2(m1(K 2 + k3) + m2(K 1 + k2)) − k22 + ((K 1 + k2)(K 2 + k3) = 0
λ = w2
m1m2λ2 − λ(m1(K 2 + k3) + m2(K 1 + k2)) − k22 + ((K 1 + k2)(K 2 + k3) = 0
λ
λ1,2 = m1(K 2+k3)+m2(K 1+k2)±
√ m1(K 2+k3)+m2(K 1+k2)−4m1m2(−k22+((K 1+k2)(K 2+k3))
2m1m2
w1,2
w1 =√ λ1
w2 =√ λ2
w1 w2
X 1 X 2
w1 w2
r1 = x
(1)2
x(1)1
= k1+k2−m1w21
k2
r2 = x
(2)2
x(2)1
= k1+k2−m1w22
k2
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X 2 = r1X 1
X 1
(1)1
(1)2
(1)1
1X (1)1
X 2
(2)1
(2)2
(2)1
2X (2)1
X (1)1 (t)
(1)1 (t)
(1)2 (t)
(1)
1 cos(w1t + φ1)
1X (1)1 cos(w1t + φ1)
X
(1)2 (t)
(2)1 (t)
(2)2 (t)
(2)1 cos(w2t + φ2)
2X (2)1 cos(w2t + φ2)
X 1(t) = X (1)1 cos(w1t + φ1) + X
(2)1 cos(w2t + φ2)
X 2(t) = r1X (1)1 cos(w1t + φ1) + r2X
(2)1 cos(w2t + φ2)
X (1)1 =
1r2−r1
(r2x1(0) − x2(0))2 + 1w21 (
˙x2(0) − r2 ˙x1(0))2
X (2)1 =
1r2−r1
(x2(0) − r1x1(0))2 + 1w22 (r1
˙x1(0) − ˙x2(0))2
φ1 = tan−1(
˙x2(0)−r2 ˙x1(0)w1(r2x1(0)−x2(0)
)
φ2 = tan−1( (r1
˙x1(0)− ˙x2(0)w2(x2(0)−r1x1(0))
)
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m1 = 10Kg
m2 = 1Kg
K 1 = 30N m
K 2 = 5N m
x1(0) = 1m
x2(0) = 0
ẋ1(0) = 0
ẋ2(0) = 0
r1 = 2
r2 = −5
m1ẍ + (K 1 + k2)x1 − k2x2 = 0
m2ẍ + K 2x2 − k2x1 = 0
M Ẍ + KX = 0
m1 00 m2
ẍ1ẍ2
1 + k2 2
2 2
x1x2
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10kg 0
0 1kg
ẍ1ẍ2
x1x2
00
| − Mw2 + k| 2
2
10kg2w4 − w2(50kgN m + 35kgN m) − 25N m + 175N m = 0
10kg2w4 − w285kg N m
+ 150N m
= 0
10kg2λ2 − 85kgN mλ + 150N m = 0
λson :
λ1 = 2,5
λ2 = 6
w1 = √
2,5 = 1,5811 rads
w2 =√
6 = 2,449 rads
r1 = x
(1)2
x(1)1
= 35N/m−10kg∗(1,5811 rad
s )2
5N/m = 2
r2 = x
(2)2
x(2)1
= 35N/m−10kg∗(2,449 rad
s )2
5N/m = −5
X (1)1 =
1−5−2
(−5 ∗ 1m)2 + 12,5
(0)2
X (1)1 =
1−5−2
(−5 ∗ 1m)2 + 12,5(0)2 = −0,71428m
X (2)1 =
1−7
(−(2) ∗ 1m)2
φ1 = tan−1(
˙x2(0)−r2 ˙x1(0)w1(r2x1(0)−x2(0)
)
φ1 = tan−1( 0
1,5811 rads (−5∗1m)
) = 0
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φ2 = tan−1( (r1
˙x1(0)− ˙x2(0)w2(x2(0)−r1x1(0))
)
φ2 = tan−1( 0
2,449 rads ∗(−2∗1m)
) = 0
X 1
(1)1
(1)2
X 2
(2)1
(2)2
X (1)1 (t)
(1)1 (t)
(1)2 (t)
X (1)2 (t)
(2)1 (t)
(2)2 (t)
X 1(t) = −0,71428 ∗ cos(1,5811 rads t) + 0,285m ∗ cos(2,449 rads t)
X 2(t) = −1,42856m ∗ cos(1,5811 rads t) − 1,425m ∗ cos(2,449 rads t)
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