Calculo de Instalacion de Calefaccion Bitubular
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Diapositiva 1
INSTALACIONES-2DEPARTAMENTO DE CONSTRUCCIONES ARQUITECTNICAS
CURSO
08-09
Profesor: Dr. D. Julin Domene Garca
4 C
DISEO Y CLCULO DE LAINSTALACIN DE CALEFACCINBITUBULAR EN UNA VIVIENDA
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Diapositiva 2
EJEMPLO DE CLCULO
2
Se dispone de una vivienda unifamiliar de129 m de superficie til, ubicada en Bilbao.Cuyas caractersticas geometricas sepueden observar:
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Diapositiva 3
EJEMPLO DE CLCULO
3
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Diapositiva 4
4
Resumen de las prdidas totales en la vivienda:
SUMATOTAL 10.115 W
Local QSI Infiltraciones QT
Saln 3.757 472 4.229
Bao 239 22
261
Cocina 678 56
734
Dormitorio 1 735 127
862
Dormitorio 2 993 213
1.206
Dormitorio 3 604 53
657
Dormitorio 4 991 278 1.269
Vestbulo 787 110
897
Prdidas totales= prdidas por transmisin + prdidas por infiltraciones:
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Diapositiva 5
5
Con estos valores, se tendr que hallar elmodelo de radiador idneo para suministrarsta potencia en las condiciones establecidas.
Los radiadores se montan en la viviendacompletamente exentos, debajo de lasventanas, con lo cual el rendimiento de los
mismos ser el mximo, es decir el 100 %.
SELECCIN DE LOS RADIADORES
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Diapositiva 6
6
SELECCIN DE LOS RADIADORES
Los valores expuestos en la tabla siguiente, estncalculados para salto trmico de 60 C,correspondientes a la antigua norma UNE 9015,sustituida por la norma europea UNE-EN 442,despus de la entrada en vigor del RITE, en la cualsu valor es de 50 C. Encontrando la diferenciaposteriormente.
Los radiadores se han elegido delcatlogo general de la marca comercialRoca.
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Diapositiva 7
7
TEMA 7
1. Saln comedor:Prdidas 4.229 W = 3.636 Kcal/h
1 radiador
2 radiadores
Clculo de los radiadores
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Diapositiva 8
8
TEMA 7 Prdidas Saln = 4.229 W = 3.636 kcal/h
2 Radiadores Dubal 70, Emisin = 1.196,3x2 = 2.392,6 kcal/h
Con 7 elementos cada uno
1 Radiador Dubal 30, de 1.273,5 Kcal/h
Con 15 elementos
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Diapositiva 9
9
TEMA 7
1. Saln comedor:Prdidas 4.229 W = 3.636 Kcal/h
1 radiador 1.273 Kcal/h
2 radiadores 2.393Kcal/h
SUMA 3.666 Kcal/h
Clculo de los radiadores
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Diapositiva 10
EJEMPLO DE CLCULO
10
1
2 34
5
67
8 9
10
11
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Diapositiva 11
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Local W Kcal/h N Radiador Elementos Emisincalorfica
Saln 4 .229 3.6361
2 y 3Dubal 30
2xDubal 7015
2x71.273
2x1.196
Bao 261 224 4 Dubal 30 3 255
Cocina 734 631 5 Dubal 45 6 677
Dormitorio 1 862 741 6 Dubal 60 6 886
Dormitorio 2 1.206 1.037 7 Dubal 70 7 1.196
Dormitorio 3 657 565 8 Dubal 45 6 677
Dormitorio 4 1.269 1.091 9 Dubal 70 7 1.196
Vestbulo 897 771 10 y 11 Dubal 45
Dubal 3044
451340
10.115 8.697 72 9.343
De la misma manera y resumiendo:
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Diapositiva 12
12
Queda definido el caudal de agua que circula por el dispositivoemisor, como:
C = Q/cxt
En la que:
C = caudal msico de agua que circula por el emisor en kg/s.
Q = potencia calorficaen W
t = diferencia temperat ura de entrada y s alida del emisor
C = calor especfico del agua 4.185 J (kg C)
Se toma como base para el clculo una diferencia de 20C
Con lo que en el saln-comedor:
C = 3.636/4.185x20 = 0,043kg/s
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Diapositiva 13
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El restode valores:
Local W Kc al /h N Ra dia do r Ele me nt os Emisincalorfica Caudal
Saln 4 .229 3.6361
2 y 3Dubal 30
2xDubal 7015
2x71.273
2x1.196 0,043
Bao 261 224 4 Dubal 30 3 255 0,003
Cocina 734 631 5 Dubal 45 6 677 0,009
Dormitorio 1 862 741 6 Dubal 60 6 886 0,01
Dormitorio 2 1.206 1.037 7 Dubal 70 7 1.196 0,014
Dormitorio 3 657 565 8 Dubal 45 6 677 0,008
Dormitorio 4 1.269 1.091 9 Dubal 70 7 1.196 0,015
Vestbulo 897 771 10 y 11 Dubal 45
Dubal 3044
451340
0,011
10.115 8.697 72 9.343 0,113
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Diapositiva 14
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sta es sustituida por la norma europea UNE-EN442, despus de la entrada en vigor del RITE, enla cual su valor es de 50 C. Encontrando la
diferencia posteriormente.
Los valores expuestos en la tabla siguiente, estncalculados para salto trmico de 60 C,correspondientes a la antigua norma UNE 9015.
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Diapositiva 15
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TEMA 7 Prdidas Saln = 4.229 W = 3.636 kcal/h
2 Radiadores Dubal 70, Emisin = 1.191,3x2 = 2.382,6 kcal/h
Con 10 elementos cada uno
1 Radiador Dubal 30, de 1.283,4 Kcal/h
Con 18 elementos
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Diapositiva 16
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Comparacin entre las normas UNE 9015 y UNE-EN 442-Radiadores
Norma UNE9015 (60C)
Norma UNE 442(50C)
Local W Kcal/h N Radiador Elementos Emisin
calorfica Radiador Elementos Emisin
calorfica
Saln 4.229 3.6361
2 y 3Dubal 30
2xDubal 7015
2x71.273
2x1.196Dubal 30
2xDubal 70
182x10
1.2832x1.191
Bao 261 224 4 Dubal 30 3 255 Dubal 30 4 285
Cocina 734 631 5 Dubal 45 6 677 Dubal 45 8 635
Dormitorio 1 862 741 6 Dubal 60 6 886 Dubal 60 8 831
Dormitorio 2 1.206 1.037 7 Dubal 70 7 1.196 Dubal 70 10 1.191
Dormitorio 3 657 565 8 Dubal 45 6 677 Dubal 45 8 635
Dormitorio 4 1.269 1.091 9 Dubal 70 7 1.196 Dubal 70 10 1.191
Vestbulo 8 97 771 10 y 1 1 Dubal 45
Dubal 3044
451340
Dubal 45Dubal 30
65
477356
10.115 8.697 72 9.343 87 9.266
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Diapositiva 17
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Como se aprecia la aplicacin del salto trmicode la UNE-EN 442 (10) supone un aumento deldoble en lo referente al gasto, y por lo tantoconlleva un sobredimensionamiento de lastuberas.
En cuanto a los caudales:
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Diapositiva 18
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Comparacin entre las normas UNE 9015 y UNE-EN 442CAUDALES
Norma UNE9015 (60C)
Norma UNE 442(50C)
Local W Kcal/h N Elemento
sEmisincalorfica Caudal
Elementos Emisincalorfica Caudal
Saln 4.229 3.6361
2 y 315
2x71.273
2x1.196 0,043 18
2x10
1.2832x1.191 0,086
Bao 261 224 4 3 255 0,003 4 285 0,006
Cocina 734 631 5 6 677 0,009 8 635 0,018
Dormitorio 1 862 741 6 6 886 0,01 8 831 0,02
Dormitorio 2 1.206 1.037 7 7 1.196 0,014 10 1.191 0,028
Dormitorio 3 657 565 8 6 677 0,008 8 635 0,016
Dormitorio 4 1.269 1.091 9 7 1.196 0,015 10 1.191 0,030
Vestbulo 8 97 771 10 y 1 1 4
4451340
0,011 6
5
477356 0,022
10.115 8.697 72 9.343 0,113 87 9.266 0,226
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Diapositiva 19
Distribucin instalacin tuberas
19A
B
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Diapositiva 20
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RED HIDRULICA DE CALEFACCINDISTRIBUCIN
RAMAL 1
RAMAL 2
AB
C D E F
G H I J K
RAD 1Comedor-Estar
RAD 2
Comedor-Estar
RAD 3
Comedor-Estar
RAD 4
Bao
RAD 5
Cocina
RAD 6Dormitorio 1
RAD 7Dormitorio 2
RAD 8Dormitorio 3
RAD 9Dormitorio 4
RAD 10Pasillo
RAD 11Vestbulo
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DISEO DE LA RED DE TUBERIAS
Norma UNE9015 (60C)
Norma UNE 442(50C)
N Elementos Caudal Elementos Caudal (kg/s)
12 y 3
152x7 0,043
182x10
0,0,86
4 3 0,003 4 0,006
5 6 0,009 8 0,018
6 6 0,01 8 0,02
7 7 0,014 10 0,028
8 6 0,008 8 0,016
9 7 0,015 10 0,030
10 y 11 4
4 0,011
65
0,022
72 0,113 87 0,226
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DISEO DE LA RED DE TUBERIAS
Norma UNE 442(50C)
N Elementos Caudal (kg/s) Kg/h l/h
12 y 3
182x10
0,086 310
4 4 0,006 21,6
5 8 0,018 64,8
6 8 0,02 72,0
7 10 0,028 100,8
8 8 0,016 54,1
9 10 0,030 108,0
10 y 11 6
5 0,022 79,2
87 0,226 810,5 810
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DISEO DE LA RED DE TUBERIAS
Caudal total: 426,9 + 383,6 = 810,5
Ramal 1 Kg/h l/h Ramal 2 l/h l/h
2 100 1 110 110
3 100 200 11 36,2 146,2
5 64,8 264,8 6 72 218,2
8 54,1 318,9 10 43 261,2
9 108 426,9 4 21,6 282,8
7 100,8 383,6
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RED HIDRULICA DE CALEFACCINCAUDALES
RAMAL 1
RAMAL 2
AB
C D E F
G H I J K
RAD 1Comedor-Estar
RAD 2
Comedor-Estar
RAD 3
Comedor-Estar
RAD 4
Bao
RAD 5
Cocina
RAD 6Dormitorio 1
RAD 7Dormitorio 2
RAD 8Dormitorio 3
RAD 9Dormitorio 4
RAD 10Pasillo
RAD 11Vestbulo
810,5
426,9
383,6
108
318,9
54,1
264,8
64,8
200
100
100
100,8
282,8
21,6
261,2
43
218,272
146,2
36,2
110
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Diapositiva 25
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CLCULO DE LA RED HIDRULICA DECALEFACCIN
Se utilizar tubera de cobre para la ejecucin del circuito detuberas.
El clculo se efectuartratandode minimizar las prdidasde carga
Aunque la normativa prev que stas no superen los 40mmcda/m, usualmente se trabaja con prdidas entre 12 y16 mmcda/m. Sin sobrepasar los 20.
Por lo tanto, en nuestro caso se elegirn dimetrossuficientementegrandes para que estoocurra.
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Diapositiva 26
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Podemos encontrar los dimetros en el bacocorrespondiente a las tuberas de cobre, teniendo en cuentaas mismo la velocidad del agua, que segn el RITE, nodebe pasar de 0,5 m/s en los montantes y 1,5 en losdistribuidores.
NOTA:
El anterior reglamento, recomendaba que la prdida de carga fuera inferior a 40 mmcdapor metro, y la velocidad de 2 m/s en locales habitados y 3 en tuberas enterradas.
CLCULO DE LAS TUBERAS
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DISEO DE LA RED DE TUBERIAS- RAMAL - 1
Norma UNE 442(50C)
Tramo l/h l/m
A-B 810 13,5
B-C 426 7,1
C-D 318 5,3
D-E 265 4,4
E-F 200 3,3
F-1 100 1,6
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13,5 l/m
V=1 m/s
TRAMO A-B
Dimetro interior 20 mm (Tubo de cobre de 22x1)
Prdidas de carga 20 mmcda/m
V=0,65 m/s
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En el punto B, la tubera se bifurca en dos ramales, uno para lateral de lavivienda, siendo:
Tramo Q D VPrdida de
carga
unitaria
L
A-B l/m mm m/s Mmcda/m m
13,5 20 0,65 20 7,1
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30
Tramo Q D VPrdida de
carga
unitaria
L
A-B 13,5 20 0,65 20 7,1
B-C 7,1 16,5 0,38 14 0,65
C-D 5,3 14,5 0 ,37 14 4,15
D-E 4,4 14,5 0 ,33 12 7,95
E-F 3,3 14,5 0,25 7 1,25
F-2 1,6 10,5 0 ,23 9,5 6,3
C-9 10,5 0,22 8 2,4
D-8 10,5 0,20 9 2,66
E-5 8,5 0,20 9 1,77
F-3 10,5 0,23 9,5 1,77
RAMAL 1
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Tramo L D V
Prdida
de carga
unitaria
B-G 4,65 16,5 0,33 10
G-H 3,05 14,5 0,33 12
H-I 1 14,5 0,28 9
I-J 0,95 14,5 0,25 7
J-K 4,85 12,5 0,23 7
G-7 2,96 10,5 0,2 7
H-4 3,61 8,5 0,1 2,5
I-10 1,92 8,5 0,11 3
J-6 5,96 10,5 0,16 4,3
K-11 2,66 8,5 0,14 4,5
K-1 13,70 10,50 0,24 10
RAMAL 2
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RED HIDRULICA DE CALEFACCINDIAMETRO TUBERIAS
RAMAL 1
RAMAL 1
AB
C D E F
G H I J K
RAD 1Comedor-Estar
RAD 2
Comedor-Estar
RAD 3
Comedor-Estar
RAD 4
Bao
RAD 5
Cocina
RAD 6Dormitorio 1
RAD 7Dormitorio 2
RAD 8Dormitorio 3
RAD 9Dormitorio 4
RAD 10Pasillo
RAD 11Vestbulo
20 mm
16,5
16,5
10,5
14,5
8,5
14,5
8,5
14,5
10,5
10,5
10,5
14,5
8,5
14,5
8,5
10,5
12,5
8,5
10,5
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El paso siguiente consistir en mostrar de que forma puede estimarsela prdida de carga principal (nicamente de los tramos rectos de lastuberas)de la lnea de alimentacinde los radiadores.
Prdidas de carga principales
Se tendr que determinar qu circuito es el que genera una mayorresistenciaal paso del lquido.
Parece lgico que ser el de mayor longitud, en nuestro caso setratardel ramal II.
El circuito hidrulico completo, con la lnea de retorno, se puede veren el siguiente esquema:
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Prdidas de carga principales
RAMAL 1
RAMAL 2
RadiadorDormitorio 2
RadiadorBao
RadiadorPasillo
RadiadorDormitorio 1
RadiadorVestbulo
RadiadorComedor-Estar
CALDERA
A A
B
B
GHIJK
111 6 10 4 7
1.480 555 966
415 332
1.385
5.133 W
2.035 3.0013.416
3.748
Potencia calorfica 10.7 76 W
Para estimar las prdidas de carga
principales se confecciona la tablasiguiente
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Prdidas de carga principales
Datos de los planos de tuberas Clculos hidrulicos
Capacidad delramal
Caudal deagua
Longitud deltramo Dimetro
Velocidaddel fluido
Prdida decarga unitaria
Prdida decarga del tramo
C L D V Hf/L hf
Tramo W Kg/h M mm m/s mmcda mmcda
AB 10.776 810 7,1 20 0,47 15 107,7
BG 5.133 383,6 4,65 16,5 0,33 10 46,5
GH 3.748 282,8 3,05 14,5 0,33 12 36,6
HI 3.416 261,2 1 14,5 0,28 9 9
IJ 3 .001 218,2 0,95 14,5 0,25 7 6,7
JK 2.035 146,2 4,85 12,5 0,23 7 34
K1 1.480 110 13,7 10,5 0,24 10 137
Prdidas de carga debidas a la longitud de la tuberia de ida ( sin accesorios) 337,5
Las perdidas de carga debidas a la longitud de la tubera de ida ms larga (ramal 2) sin tener encuenta la existencia de resistencias aisladas (accesorios) son de 337,5 mmca
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Sabiendo que las prdidas de carga originadas por codos, llaves,radiadores, vlvulas, etc., suponen aproximadamente del 30 al 50 % delas prdidas totales, que son las que deber vencer la bomba,sirvindonos para su clculo.
En nuestro caso sern:
337,5 x 0,50 = 169 mmcda
Prdidas de carga secundarias
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Sern la suma de las calculadas, principales y secundarias, de talforma que:
337,5 + 169 = 506,5 mmcda
Prdidas de carga totales
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Segn el caudal calculado de 6,4 l/m,equivalente a 0,38 m/h y una prdida decarga total de 5,06 mcda, segn las curvasde caudal presin de Roca:
38
Clculo de la bomba aceleradora
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Clculo de la bomba aceleradora
0,38 m/h
5,06 mcda
PC-1055
7,6
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Actualmente la bomba de circulacin se encuentra, lamayor parte de veces instalada en el conjunto de lacaldera. Por esto el fabricante, que conoce sta, decide sutipo y caractersticas.
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La potencia de la caldera o calderas, debe ser capaz desuministrar la debida a la calefaccin y la necesaria para ACS,siempreque el grupo trmico mixto sea inferior a 70 KW.
l cul o de l a cal der a y el quemador
Ser la necesaria para contrarrestar las prdidas de calor atravs de los elementos constructivos, el aire de renovacindebido a la infiltracin e incluso la prdida de calor disipada enlas tuberas.
La Directiva Europea 92/42/CEE, exige que los generadorestengan un rendimiento mnimo en funcin de su potencia til ysegn el tipo de combustible. RD 275/1995.
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l cul o de l a cal der a y el quemador
El clculo de la caldera se realiza:
Potencia total demandada = QT=(SQ1+SQ2)xA
Q1=potenciacalculada en radiadores (kcal/h)
Q2=potenciadisipada en tuberas
A=aumentode inerciade valor 1,2
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En nuestro caso:
Potenciacalculadaradiadores= 9.266 w = 9,26 kw
Potenciatotal = (9,26/0,95) 1,2 = 11,64 kW.
Se adoptar una caldera tipo Lidia,modeloLidia20 GT, de Roca.
Grupo trmico de fundicin, para instalaciones de calefaccinpor agua caliente hasta 4 bar y 100 C.
De 15000 kcal/h (17,4 kW), y resto de caractersticas que se
pueden observar en:
l cul o de l a cal der a y el quemador
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En cuanto al quemador, igual que la bomba, el fabricante, porconocer las caractersticas de la caldera, procede a la seleccindel mismo. En nuestro caso un quemador de gasoil Neotronic ykadet-tronic,modelo , 2RS-L, integradoen el conjunto.
l cul o del quemador
Cumplir lo establecido en la IT correspondiente, en cuanto a suregulacin. Bsicamente se elige en funcin de la longitud yanchurade la llama.
El consumo horario de combustible viene expresado por la
expresin:Q = Qt/Pci x
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Se deben cumplir una serie de consideraciones con estoselementos:
Es recomendable un vaso de expansinpor caldera
La alimentacin del agua al sistema no puede realizarse conuna conexin directa a la red de distribucin urbana. Se debehacer preferiblemente por el vaso.
No debe existir ningn elemento de corte entre la caldera y elvaso de expansin.
l cul o del vaso de expansin
Debe calcularse el contenido de agua de la instalacin llena,contando todos los elementos que la componen, radiadores,
tuberas y caldera, que junto al factor de dilatacin del agua,nos proporcionar la capacidad del vaso
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l cul o del vaso de expansin
Si es abierto,se debe calcular segn la norma UNE100155-88.
Su volumenser:
Vv=0,06xVt
Vt, es el volumen total de agua incluyendo el de la tubera deconexindesde lacaldera al vaso, que tendr un dimetrode:
D = 15+1,5vP
P=potencia instalada en kW, en todo caso, D=25 mm (segn UNE100157-89)
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En nuestro caso, ser un vaso de expansin cerrado,con compresor, con lo cual:
Vu= Vxfd
Vu=volumen til del vaso
V= Volumen del agua de la instalacin
Fd= Factor de dilatacin, que en la EN 442, adopta como valor medio la temperatura de 70 C
l cul o del vaso de expansin
Dilatacin del agua
10 C 0,027 %
20 C 0,177 %
30 C 0,435 %
40 C 0,782 %
50 C 1,21 %
60 C 1,71 %70 C 2,27 %
80 C 2,90 %
90 C 3,59 %
100 C 4,34 %
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l cul o del vaso de expansin
V, tendr un valor:
Radiadores: 68 elementosx 0,43 litros + 19x0,36 = 36,08 litros
Caldera:13 litros
Tuberas: 71 m x 0,079 l/m = 5,6 litros ( Segn tabla norma UNE-EN1057)
Factor de dilatacin: 0,0228 (temperatura 70 C, EN 442).
El volumen del vaso ser tan pequeo que:
Se dispondr de un modelo vasoflex de Roca de 8 litros decapacidad, que cumplircon lo quese necesita.
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La cantidad de agua a evacuar por la vlvula de seguridad secalcula:
G = Q/500
G = capacidad de descarga
Q = potencia de la instalacin en kcal/h (o en kW)
Vlvul a de seguridad
La tubera de descarga, la encontramos en la tabla 2 de la normaUNE 100157-89, donde la obtenemos directamente en funcin dela potenciade la instalacin.
El dimetro mnimo de sta, ser de 20 mm.
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Se calcula para una reserva de un mes, considerando el de Enero. Por medio del mtodode los grados-da:
Capacidad depsito combustible
Donde: V=Volumen depsito de combustible
Q=Potencia de la caldera (kcal/h)
G=nmero de grados-da mes de Enero (UNE 24026)
V=coeficiente de uso
I=coeficiente de intermitencia
R=rendimiento de la instalacin=0,85P=poder calorfico de la unidad de combustible (10500 kcal/kg, para el gasleo C)
352
1050085,025
85,01243,2571500024
PRtt
IvGQV
ei
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IT 1.3.4.1.3.1 Evacuacin de los productos de lacombustin
Chimenea
La evacuacin de los productos de la combustin enlas instalaciones trmicas se realizar de acuerdocon las normas generales expuestas en el prrafoanterior.
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En los edificios de nueva construccin en losque se prevea una instalacin trmica, laevacuacin de los productos de lacombustin del generador se realizar por unconducto por la cubierta del edificio, en elcaso de instalacin centralizada.
Chimenea
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IT 1.3.4.1.3.2 Diseo y dimensionado de chimeneas
Chimenea
Es vlido el dimensionado de las chimeneas de acuerdo a loindicadoen las normas:
UNE-EN 13384-1
UNE-EN 13384-2
UNE 123001, segn el caso.
La chimenea ser de material resistente a la accin agresiva de losproductos de la combustin y a la temperatura, con la estanquidadadecuadaal tipo de generador empleado.
En el caso de chimeneas metlicas la designacin segn la normaUNE-EN 1856-1 o UNE-EN 1856-2 de la chimenea elegida en cadacaso y para cada aplicacin ser de acuerdo a lo establecido en lanorma UNE 123001.
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Para la evacuacin de los productos de lacombustin de calderas, la seccin de la chimenea,su material y longitud sern los certificados por elfabricante de la caldera.
Chimenea
Pero conociendo la potencia de la instalacin (kcal/ho kW) as como la altura de la chimenea, la obtencindel dimetro es inmediata, por medio del diagrama
comercial. Siendo ste el procedimiento ms seguro.
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Chimenea
La seccin de los conductos de humo, secalcula de acuerdo con el volumen de gasesprevisibles, segn la expresin de Sander,con la cual se hacen los bacoscorrespondientes:
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S = 213 cm
Seccincircular:
213 = 3,14x R con loque
R = 8,25 cm
Con estos datos:
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