Datos Transmisor

Barabón 2°53’34.4’’ S79°5’15.1’’ W

ReceptorCerro Buerán

2°36’31.1’’ S78°55’50.9’’ W

Calculo de la distancia

Primero obtenemos la latitud y longitud en radianes. Transmisor

LatitudXT=2 °53 ’34.4 ’ ’ S=−2.892888889 °

XT=−0.050490436 radianes

LongitudY T=79 °5 ’15.1 ’ ’W=−79.08752778 °

Y T=−1.380337757 radianes

ReceptorLatitud

X R=2° 36 ’31.1 ’ ’ S=−2.608638889 °

X R=−0.045529338 radianes

LongitudY R=78 ° 55’ 50.9’ ’W=−78.93080556 °

Y R=−1.377602438 radianes

Ahora procedemos a calcular la distancia.

D=6371∗cos−1(sen (XT )∗sen ( XR )+cos (XT )cos (X R )cos (Y R−Y T ))

D=6371∗cos−1(sen (−0.0504 )∗sen (−0.0455 )+cos (−0.0504 )cos (−0.0455 ) cos ((−1.3776)−(−1.3803)))

D=36.08327565 km

Calculo de los azimuth

Transmisor-Receptor

a tr=cos−1(sen ( XR )−sen (D ) sen ( XT )

sen (D )cos (XT ))

a tr=cos−1(sen (−0.0455 )−sen (36.0832 ) sen (−0.0504 )

sen (36.0832 ) cos (−0.0504 ))

a tr=1.522882492 radianes

a tr=87.25473948 °

Receptor- Transmisor

art=cos−1(sen ( X t )−sen (D ) sen (X r )

sen (D ) cos ( X r ))

art=cos−1(sen (−0.0504 )−sen (36.0832 ) sen (−0.0455 )

sen (36.0832 )cos (−0.0455 ))

ar t=86.98335479 °

Ahora revisamos la condición

a tr art=360−art Cuando sen (Y R−Y T )>0

a t r=360−atr art Cuando sen (Y R−Y T )<0

Calculamos

sen (Y R−Y T )=sen(−1.377602438−(−1.380337757))

sen (Y R−Y T )=0.002735315

Entonces

sen (Y R−Y T )>0

Por lo tanto

a tr=87.25473948 °

art=360−art=360−86.98335479

art=273.0166452 °