ejercicio microodas
1
Ing. Cesar Gerónimo Mayor [email protected] 511 993637230 Lima PERU Pregunta Se sabe que la relación C/N en recepción es 37.37dB. Calcular la distancia del enlace en Km. Solución: dBm PIRE dB dB dB dB dBm PIRE dBm C dBm C dB N C N C dBm N x dB N B dB NF To dBm N 3 . 59 32 2 . 1 3 5 . 0 32 55 ) 38 . 92 ( 37 . 37 38 . 92 30 ) 10 18 log( 10 9 ) 293 log( 10 6 . 228 30 ) log( 10 ) ( ) log( 10 6 . 228 ) ( 6 = + - - - = - = - - = - = - = + + + + - = - = Km d d d MHz d dB f d Ao dB Ao Ao PIRE IRL dBm IRL dB dB dBm IRL Km 06 . 25 98 . 27 ) log( 20 82 . 79 4 . 32 2 . 140 ) log( 20 ) 9800 log( 20 ) log( 20 4 . 32 2 . 140 ) log( 20 ) log( 20 4 . 32 2 . 140 9 . 80 26 1 . 0 55 = = - - = + + = + + = = - = - = - - = T X 1/2 1/2 32dBm (0.5 dB) (0.1 dB) (1.2dB) 2 2 G = 26dB G = 32dB Rx2 d 1 = ? f 2 = 9.8GHz C/N = 37.37 dB B = 18MHz To = 293ºK NF = 9dB
-
Upload
cesar-geronimo -
Category
Documents
-
view
220 -
download
3
description
microodas ejemplo
Transcript of ejercicio microodas
Ing. Cesar Gerónimo Mayor [email protected] 511 993637230 Lima PERU
Pregunta Se sabe que la relación C/N en recepción es 37.37dB. Calcular la distancia del enlace en Km.
Solución:
dBmPIRE
dBdBdBdBdBmPIRE
dBmC
dBmCdB
NCN
C
dBmN
xdBN
BdBNFTodBmN
3.59
322.135.032
55
)38.92(37.37
38.92
30)1018log(109)293log(106.228
30)log(10)()log(106.228)(6
=+−−−=
−=−−=
−=
−=++++−=
++++−=
Kmd
d
d
MHzddB
fdAo
dBAo
AoPIREIRL
dBmIRL
dBdBdBmIRL
Km
06.25
98.27)log(20
82.794.322.140)log(20
)9800log(20)log(204.322.140
)log(20)log(204.32
2.140
9.80
261.055
==
−−=++=
++=
=−=
−=−+−=
TX 1/2
1/2
32dBm
(0.5 dB)
(0.1 dB)
(1.2dB)
2 2
G = 26dB
G = 32dB
Rx2
d1 = ?
f2 = 9.8GHz
C/N = 37.37 dB B = 18MHz To = 293ºK NF = 9dB
