FORMULARIO MAQUINARIA

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Seca 0.35 0.40 Hùm eda 0.20 0.35 Mojada 0.10 0.30 Superficie del tambor sin recubrimiento con recubrimiento TABLA XXIV TAMBOR EN CABEZA TAMBOR EN COLA COMB T 2= FT1 e μα 1 T 2= FT1 e μα 1 F 2=FT∗[ e μ 2 α2 1 e μ 2 α2 e μ 1 α1 1 ] T 1=T 2+FT T 1=T 2+FT PB= Pfaj/ LPQ=Pmin / L T 3=T 4=T 2+( FiHPB) T 3=T 4=T 1+( HPBFi ) Pmoviles=2 PB+ Ps +Pi T 4 <T 1=¿ T 4= T 1 T 2 <T 1=¿ T 2=T 1 F 1=FT F 2 T 3=T 4=T 1 T 1=T 2+FT T 1=F 1 ( 1+ 1 e μ1 α 1 1 ) ANGULO DE LA CINTA ASCENDENTE/DESCEND ENTE (grados) COEFICIENTE DE REDUCCION (K) 2 1.00 4 0.99 6 0.98 8 0.97 10 0.95 12 0.93 14 0.91 16 0.89 18 0.85 20 0.81 21 0.78 22 0.76 23 0.73 24 0.71 25 0.68 26 0.66 27 0.64 28 0.61 29 0.59 30 0.56 ɸ RODILLO f 4" 0.0375 5" 0.0360 5.5" 0.0330 6" 0.0300 6.5" 0.0275 7" 0.0250 B1=0.9B- 0.05 B<=2 RS=(L-2)*3 +3*(2 || 3) B1=B-0.25 B>2 RI=(L-1) TABLA 30-60 J 1.5 T2A=J+T2 TU=Effmax* F Tent=T2A+TU 1 M3=2.1 Ton C=0.087 ln ( LONG ) 2 1.31ln ( LONG) +5.9 7 Q=3600VKS(ton/h) S=ab sin ( θ ) +b 2 cos ( θ) sin ( θ)+ 0.067 ( a + 2 b cos ( θ)) 2 Rc= [ ( PQ+ PB +Ps ) f cos δ± ( PQ +PB ) sinδ ] L Rv = [ ( PQ+ Pi ) fcosδ ±PQsinδ ] L PQ = Q 3.6 V ; PB=( Pc +Pr ) B ; Q= Vim ( D 2 d 2 ) 183.33 (cfm) Fs= c fL [ ( PQ +PB ) cosδ +Ps ] ; Xlt∗( 3.21 3.785 ) Fi= c fL [ PB cosδ +Pi ] ; ANF=1.94 ; EMUL=1.78 FT =cfL [ ( PQ +2 PB ) cosδ +Ps +Pi ] ±HPQ Vim =54600 ¿ ; ρ : lb pie 3 ; Dp : pies W 1= F 1V 75 ( CV ) W 2= F 2V 75 ( CV ) PR 1= W 1 n ( HP ) PR 2= W 2 n ( HP ) V=tabla=1.8 n=eficiencia

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formulario maquinaria minera primera unidad

Transcript of FORMULARIO MAQUINARIA

Page 1: FORMULARIO MAQUINARIA

Seca 0.35 0.40Hùmeda 0.20 0.35Mojada 0.10 0.30

Superficie del tambor

sinrecubrimiento

conrecubrimiento

TABLA XXIV

TAMBOR EN CABEZA TAMBOR EN COLA COMB

T 2=FT∗1eμα−1

T 2=FT∗1eμα−1

F2=FT∗[ eμ2α 2−1eμ2α 2∗eμ1α 1−1

]

T 1=T 2+FT T 1=T 2+FT PB=Pfaj /LPQ=Pmin /LT 3=T 4=T 2+(Fi−HPB) T 3=T 4=T 1+(HPB−Fi) Pmoviles=2 PB+Ps+PiT 4<T 1=¿T 4=T 1 T 2<T 1=¿T 2=T 1 F1=FT−F2T 3=T 4=T 1 T 1=T 2+FT T 1=F 1(1+ 1

eμ1α1−1)

T 2=T 3+(HPB−Fi ) T 3=T 4=T 1+(HPB−Fi) T 2=T 1+FTT 1=FT +T 2 T 3=T 4=T 2+F1−HPB

α : radianes

ANGULO DE LA CINTA ASCENDENTE/DESCENDEN

TE(grados)

COEFICIENTE DE REDUCCION (K)

2 1.004 0.996 0.988 0.97

10 0.9512 0.9314 0.9116 0.8918 0.8520 0.8121 0.7822 0.7623 0.7324 0.7125 0.6826 0.6627 0.6428 0.6129 0.5930 0.56

ɸ RODILLO f4" 0.03755" 0.0360

5.5" 0.03306" 0.0300

6.5" 0.02757" 0.0250

B1=0.9B-0.05 B<=2

RS=(L-2)*3 +3*(2 || 3)

B1=B-0.25 B>2

RI=(L-1)

TABLA 30-60J 1.5

T2A=J+T2 TU=Effmax*FTent=T2A+TU 1 M3=2.1 Ton

C=0.087∗ln (LONG )2−1.31∗ln (LONG )+5.97Q=3600∗V∗K∗S∗∮ (ton/h)S=ab sin (θ )+b2cos (θ )sin (θ)+0.067(a+2b cos(θ))2

Rc=[ (PQ+PB+Ps ) f cos δ ±(PQ+PB)sinδ ]∗LRv=[ (PQ+Pi ) fcosδ ±PQsinδ ]∗L

PQ= Q3.6V ; PB=(Pc+Pr)B ; Q=

Vim(D2−d2)183.33

(cfm)

Fs=c∗f∗L [ (PQ+PB ) cosδ+Ps ] ;Xlt∗( 3.213.785

)

Fi=c∗f∗L [ PB cosδ+Pi ] ; ANF=1.94 ; EMUL=1.78FT=c∗f∗L [ (PQ+2 PB ) cosδ+Ps+Pi ]±HPQVim=54600∗¿ ; ρ : lb

pie 3 ; Dp : pies

W 1= F1∗V75

(CV ) W 2= F2∗V75

(CV )

PR 1=W 1n

(HP) PR 2=W 2n

(HP )

V=tabla=1.8 n=eficiencia

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F2=[ eμ2α2−1eμ2α2∗eμ1α1−1 ]∗¿]

F1=FT−F2

RI=Fi−HPB;μ1=μ1α 1=α 2 (verd) T 2=F 1∗1eμα−1

; T 1=T 2+F1

F2=[ 1eμα+1 ]FT + eμα−1

eμα+1RI

T 4=T 1−[Fs+H (PQ+PB)] ;T 3=T 4+F2