Presentasi Baja Pak Badar

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    7.5

    4

    15 15

    3 3 3

    = 0

    - RB 12 - 15 3 + 6 + 9 +

    RB = 270 + 45 + 15

    RB = 330

    12

    RB = 27.5 Ton

    Dengan cara ritter melalui pot. ! "apat "i cari #e$arn%a #atang &B

    12 = 0

    3 - 27.5 3 =

    = '2.5

    3

    = 27.5 Ton

    R#

    pa"a #atang &B #e(er)a ga%a tari( ter*a(tor Tu $e#e$ar

     T, = 1.2 0.2 27.5 + 1.6 0.' 27.5

    = 6.6 + 35.2

    = 41.' Ton

    pa"a $%arat (elang$ingan #atang tari(

    Σ c

    Σ D

    BD

    BD BD

    BD

    &B

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    λ = / = 300 = 141.5 < 240

    r min 2.12

    (on"i$i lele

    = φ *%

    = 0.9 240 2 940

    = 40.61 Ton

    (on"i$i *a(tur

    = 2 940 - 7 21 = 1733

    &m#il , = 0.'5

    = φ *%

    = 0.75 370 0.'5 1733

    = 40.'' Ton

     )a"i = 40.'' Ton > 40.61 Ton mantap pak bad

    φ Tu &g

    &g mm2

    φ Tu &g

    φ Tu

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    15

    15

    3

    7.5 6 + 15 4 = 0

    0

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    r!!

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    ' Ton

    3.5 m

    13 Ton 13 Ton

    2.5 m 2.5 m 2.5 m

    = 0

    - RB 10 - 15 2.5 + 5 + 7.5 +

    RB = 225 + 40 + 15

    RB = 2'0

    10

    RB = 2' Ton

    Dengan cara ritter melalui pot. ! "apat "i cari #e$arn%a #atang &B

    10 = 0

    2.5 - 2' 2.5 =

    = 70

    2.5

    = 2' Ton

    R#

    pa"a #atang &B #e(er)a ga%a tari( ter*a(tor Tu $e#e$ar

     T, = 1.2 0.2 2' + 1.6 0.' 2'

    = 6.72 + 35.'4

    = 42.56 Ton

    pa"a $%arat (elang$ingan #atang tari(

    Σ c

    Σ D

    BD

    BD BD

    BD

    &B

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    λ = / = 300 = 141.5 < 240

    r min 2.12

    (on"i$i lele

    = φ *%

    = 0.9 240 2 940

    = 40.61 Ton

    (on"i$i *a(tur

    = 2 940 - 7 21 = 1733

    &m#il , = 0.'5

    = φ *%

    = 0.75 370 0.'5 1733

    = 40.'' Ton

     )a"i = 40.'' Ton > 40.61 Ton

    φ Tu &g

    &g mm2

    φ Tu &g

    φ Tu

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    13 Ton

    13 Ton

    2.5 m

    ' 5 + 15 3.5 = 0

    0

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    CONTOH SOAL

    e#ua Batang Tari( Dengan rol i(u 60 6 Tunggal "engan utu B 41 i(a Bau

    itung taan tari( rencana "ari #atang ter$e#ut

    a%a Tari( = 2665.39

    /e#ar rol #8 = 60 mm

     Te#al rol t8 = 6 mm

     Tinggi Total rol g8 = 114 mm

    rmin = 11.7 mm

    /ua$&g8 = 691 mm

    an)ang #atang /8 = 10'7.30167 mm2

    % = 250 pa

    *u = 410 pa

    : = 200000 pa

    Diameter #aut = 12.7 mm

    lang(a pertiungan

    a. menentukan faktor kelangsingan

    λ = ≤ 300

    r min

    λ = 10'7.3 = 92.931' < 300

    11.7

    b. menghitung besarnya nilai Nu :

    - n = &g %

    = 691 250

    = 172750

    u = ϕ n

    = 0.9 172750

    = 155475

    n = &e u

    n = &n , u

    &n = n t

    &n = 114 - 12.7 +

    = 595.'00

    , = 1 - (arena

    / =

    , = 0.9

    n = 595.'00 0.9

    n = 219'50

    u = ϕ n

    u = 0.75 219'50.2

    u = 164'''

    Diguna(an nilai u = 164''7.65

    c. cek kekuatan

    /.; <

    mm

    2

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    u ≤ ϕ n

    2665.39 ≤ 164''' → $%arat (e(uatan terpenui

    d. cek terhadap luas bersih

    /ua$ netto ≥ '5 lua$ prol

    114 - 12.7 + 2 te#al >

    595.' >

    595.' >

    e#ua #atang tari( #erupa pelat 2 158 cm "i$am#ung(an (e pelat #eru(uran 2

    la$ meman)ang $epan)ang 20 cm pa"a (e"ua $i$in%a!

    *% = 2400 (g>cm2

    *u = 4000 (g>cm2

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    #erapa #e#an rencana u %ang "apat "ipi(ul #e#an tari( ?

    (arena (e"ua pelat %ang "i $am#ung ter#uat "ari #aan %ang $ama! ma(a #e#an r

    ole (uat tari( plat %ang le#i (ecil lua$ penampangn%a! %aitu plat 215

    (riteria "e$ain u ≤

    (e(uatan platn n "itentu(an "ari (on"i$i #ata$ lele "an *ra(tur

    a. plat lele

    u = = 0.9 *% &g

    = 0.9 2400 (g>m2

    = 64.' ton

    #. plat *ra(tur

    u = = 0.75 *u &e

    "imana

    & = &g = 2 15

    = 30 cm2

    />@ = 20

    15

    = 1.33

     )a"i , "iam#il = 0.75

    &e = & , 0.75

    = 30 0.75

    = 22.5 cm2

    u = 0.75 4000 22.5

    = 67.5 ton

    Dari (e"ua nilai (uat rencana! u %ang menentu(an a"ala nilai %ang le#i (ecil

    ga%a %ang "ipi(ul #atang tari( $epan)ang 10 meter a"ala

    #e#an mati " = 50 ton

    #e#an iu"up i = 40 ton

    rencana(an penampang #atang tari( %ang ter#uat "ari penampang "engan

    *% = 2400 (g>cm2

    *u = 4000 (g>cm2

    "engan (om#ina$i #e#an

    1.4 "

    1.2 " + 1.6 l

     &@&B

    mengitung #e#an

    #e#an rencana u

    u1 = 1.4 "

    = 1.4 50

    = 70 ton

    u2 = 1.2 " + 1.6 l

    = 1.2 50 + 1.6 40

    φ n

    φ n

    φ n

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    = 124 ton

    u2 menentu(an

    mengitung &g minimum

    ;on"i$i lele

    u ≤

    &g min = 124 = 57.41 cm2

    0.9 24000 ton>m2

    ;on"i$i *ra(tur

    u ≤ =

    &n ≥ 124

    0.75 400 100 0.9

    &n ≥ 45.9259 cm2

    φ Fy Ag

    φ Fy Ae φ Fu An U

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    t %ang "iguna(an #er"iameter 12.7

    o(

    2 6

      era"a pa"a titi( #erat prol ma(a "iam#il

    0.9 $%arat minimum 8

    410

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    '5 691

    5'7.4

    5'7.4→ $%arat lua$ terpenui

      308 cm "engan

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    ncana a(an "itentu(an

    2 15 cm2

    cm2

    A 67.5 ton

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