7/28/2019 SOLUCION MAQUINAS ELECTRICAS 1

1/5

2 2

2

2 2

0

7617.88 4 3.7

4.25

14.66776

14.667 4590.77115.1816

313 .

BB B

UTIL

g g

g g

g

Kl Kl A espiraB curva H

A in in in

KlBKl Kl A espirainB H

KlA in in in

A espira in

2

20 1 3.7 7.96 4590.771 0.04

28

6.896 6.896 4 50

50(4.25) 212.5

76 212.5 288.5

C C C mC B mB g g

C C B mB g g

C

mC

C C

C C UTIL

A B C

N I H l H l H l

N I H l H lH

l

A espira KlH curva Bin in

B A Kl

Kl

El signo negativo del Hc es porque

se tomo al revs el sentido del

flujo C corrigiendo el sentido

queda:

2 2

288.567.88 4 10.5

4.25

AA A

UTIL

Kl Kl A espiraB curva H

A in in in

10.5 28 3.7 7.96 4590.771 0.04 2.535200

A mA B mB BA A A A B B g A mA B mB g

UTIL UTIL O g

A mA B mB g

A

A

l l gN I H l H l H g

A A A

H l H l H gI A

N

2

2 2

2

2 2.5 5

0.8576

0.85 5 4.25

2 0.04 2.5 0.04 5.1816

2 8 2(10) 28

28 , 8 0.04 7.96

FISICA

l

B

UTIL l FISICA

g

mA

mC mB

A x in

fKl

A f A in in

A in

l ab af fe af ab in

l in l in

SOLUCION EXAMEN DE MAQUINAS ELCTRICAS 1

4.

7/28/2019 SOLUCION MAQUINAS ELECTRICAS 1

2/5

2 2

2

2 20

20050 5 12

4

49.5200

49.5 15493.514.04

313 .

12(10) 12(10) 15493.5(0.01)

ab cd ab cd

g g

g gg

mm ad ab mab cd mcd g

Kl Kl A espiraB B curva H H

A in in in

KlBKl Kl A espirainB H

KlA in in inA espira in

F H l H l H g

2

2

3 1 2

3

2

395

39549.4 5 90

8

90(2) 180

200 180 380

38063.5 5 18

6

18(15) 270

mm adad ad

ad

ad ad

dea dea

dea

mm dea dea mdea

mm

A espira

F A espira Kl H curva B

l in in

B A Kl

Kl

Kl A espiraB curva H

A in in

F H l A espira

F

3 2 270 395 665dea ad mm dea mm ad NI F F A espira

5.

7/28/2019 SOLUCION MAQUINAS ELECTRICAS 1

3/5

2 2

2 2

2

2

2 2

0.9

0.9 4 4.5 16.2

0.9(3 4 ) 10.8

3 0.03 4 0.03 12.2

3 0.02 4 0.02 12.1

600

60055.56 3 3.7

10.8

l

UTIL A l FISICA

UTIL B UTIL C l FISICA

gC

gA

C gC

CC C

UTIL C

f

A f A x in in

A A f A x in in

A in

A in

Kl

Kl Kl AB curva H

A in in

2

2 2

0

49.2600

49.2 15400112.2

313 .

3.7(25) 15400(0.03) 554.5

554

gC gC

gC gC

gC

mm mn mA A C mC g gC

mm mn C C gC C

mm mn B B gB B

espira

in

KlBKl Kl A espirainB H

KlA in in in

A espira in

F NI

F H l H g A espira

F H l H g

0

0

2

0

0 2

.5

554.5

554.50 22.2

25

112.1 554.5

313 .0 99.24

0.02 10.8

B UTIL B Bmm mn B B

gB

mm mnB B

B

gB mm mn

B B

B UTIL B

A espira

g A BF H l A espira

A

F A espira A espiraB H

l in in

Klin A espira

A F A espira in KlH B

g A in

2

2 2

600 745.2 1345

134583.02 16

16.2

554.5 16(10) 714.5

745.2

A C B

AA A

UTIL A

mm mn mA A mm mn A A

gB B

in

Kl

Kl Kl A espiraB H

A in in in

NI F F H l

NI A espira

Kl

SOLUCION EXAMEN DE MAQUINAS ELCTRICAS 1

5.

7/28/2019 SOLUCION MAQUINAS ELECTRICAS 1

4/5

1 1.5R 1 2.5X 2 0.02R 2 0.03X

1 6cR K

1

8

mX

K 2E1E1V 2V LZ

2I1I

PI

1cI 1mI

2

2

24000.80 0.80 8

240

S VAI A

V V

2 240 0V V

2I

2 8 30I A 10.866 cos 0.866 30fp

2 2 2 2 2

2

0.02 0.03 8 30 240 0

240.019 0.069

E R jX I V j

E V

240010

240a

1 2

2

2400.19 0.069

8 300.8 30

10P

E aE

II

a

11

1

11

1

1 1

2400.19 0.0690.4 0.069

6000

2400.19 0.0690.3 89.931

8000

0.4 0.069 0.3 89.931 0.5 36.801

C

C

m

m

C m

EI A

R

EI A

jX j

I I I A

1

1 1 1 1

1

1 1 1

2 2

0.8 30 0.5 36.801 1.098 5.252

2400.19 0.069 (1.5 2.5)(1.098 5.252 )

2401.584 0.138

2401.584 0.138 1.098 5.252 2626.441 235.062

PI I I A A

V E Z I j

V V

S V I V A j VA

S V

2 240 0 8 30 1470.805 1234.152

1470.8050.56

2626.441

salida

entrada

I V A j VA

P

P

6. a)

Tomando como referencia el

voltaje en la carga (capacitiva)

Modelo equivalente exacto

Diagrama Fasorial

7/28/2019 SOLUCION MAQUINAS ELECTRICAS 1

5/5

2cR 2mX

l

CIl

mI1

lV

2eR 2ejX

2V LZ

2I1lI

2 240 0V V

2I

10.8 cos 0.8 36.87fp

1 12 2 2 2 22 2 2 2

2

1.5 2.50.02 0.03

10 10

0.035 0.055

e e e

e

R XZ R jX R j X j

a a

Z j

1 2 2 2

1

8 36.87 0.035 0.055 240 0

240.488 0.044

l

e

l

V I Z V j

V V

2 8 36.87I A

12 2 2

12 2 2

600060

10

800080

10

cc

mm

RR

a

XX

a

1

2

240.488 0.0444.008 0.044

60

ll

C

c

VI A

R

1

2

240.488 0.0443.006 89.956

80

ll

m

m

VI A

jX j

1 2

1

1 1 1

2 2 2

8 36.87 4.008 0.044 3.006 89.956

13.010 36.853

240.488 0.044 13.010 36.853 2502.111 1873.433

240 0 8 36.87 1535.998 1152.003

l l l

C m

l

l l

I I I I

I A

S V I j

S V I j

P

1535.998

0.614

2502.111

salida

entradaP

b)

Modelo equivalente aproximado

referido al secundario

Tomando como

referencia el voltaje en

la carga (inductiva)

Diagrama Fasorial