Tarea probabilidad
2
Mares Medrano Cynthia Fernanda Por integraciòn numèrica ∫ 1 6 e x 2 dx n=5 y=f(x) X simpson 3/8 simpson 1/8 2.718281828 1x 0 54.59815 2x 1 8103.083915 3x 2 8886110.496 4x 3 x 0 72004899033 5 x 1 4.31123x10 15 6 x 2 ∫ x0 x3 e x 2 = 3 8 [ ( 2.718281828 ⧾ 8886110.496 ) ⧾ 2 ( 54.59815 ) ⧾ 3 ( 8103.083915 ) ] ⧾ Er =¿ 13329207.75 ∫ x0 x2 e x 2 = 1 3 [ ( 8886110.496 ⧾ 4.31123E15 ) ⧾ 4 ( 72004899033 ) ⧾ 3 ( 0) ] ⧾ Er=¿ 1437173192000000
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Transcript of Tarea probabilidad
Mares Medrano Cynthia Fernanda
Por integraciòn numèrica
∫1
6
ex2
dx
n=5
y=f(x) X simpson 3/8 simpson 1/8
2.718281828 1 x0
54.59815 2 x1
8103.083915 3 x2
8886110.496 4 x3 x0
72004899033 5 x1
4.31123x1015 6 x2
∫x0
x3
ex2
= 38
[ (2.718281828⧾8886110.496)⧾2 (54.59815 )⧾3 (8103.083915 ) ]⧾Er=¿
13329207.75
∫x0
x2
ex2
= 13
[ (8886110.496⧾4.31123E15 )⧾4 (72004899033 )⧾3 (0 ) ]⧾ Er=¿1437173192000000
∫1
6
ex2
dx= ∫x0
x2
ex2 ⧾ ∫
x0
x3
ex2 = 1437173205000000