TP Baja 2 Fahmi Dan Sandi
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8/18/2019 TP Baja 2 Fahmi Dan Sandi
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• Kelas Jembatan = Kelas B = 70 % BM
• Bentang Jembatan = 37,5 meter
• Jarak Gelagar Memanjang = 2,75 meter
• Lebar Jembatan = 8,4 meter
• Gaya Angn = !20 kg"m2
• Alat #enyamb$ng = Ba$t
• Jens Baja = Bj 4!
• M$t$ Betn & '() * = 30 M+a
• $-$t Al+.a = /00
A. Perencanaan Sandaran
Gambar an-aran rsntal
1 Jarak antar tang san-aran, != 470 (m
1 Men$r$t #MJJ, san-aran $nt$k +ejalan kak -ren(anakan, $nt$k 2
+embebanan ren(ana -aya layan, yat$ = !00 kg"m
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Tugas Perencanaan Struktur Baja 2
1 Beban beban n bekerja se(ara bersamaan -alam ara. menylang -an
6ertkal
engan -emkan -a+at - nter+laskan sbb
Gambar #enyebaran Beban an-aran
#er.t$ngan mmen lent$r
MB1 = !"8 ) L2 = !"8 !00 4,72 = 27/,!25 kgm
Mla+9 = !"8 ) L2 1 2
Mb
= !"8: !00 : 4,72 1 2
!25,27/
= !38,0/ Kg"m
maka
M ma: = !38,0/ kgm
Bla -g$nakan san-aran -ar ++a baja & (r($lar .all se(tn * -gn m$t$ Bj =
4! &σ = 2/2; kg"m2*
< σ
ma: M
< 3 2
2/2;
!00/,!38 cm
x
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 2
8/18/2019 TP Baja 2 Fahmi Dan Sandi
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Tugas Perencanaan Struktur Baja 2
cm Dcm x
D ;2,3 2/2;
!00/,!38
3/
! 3 2
3 ≥=≥π
-ren(anakan san-araan .rntal mengg$nakan +r'l ++a baja -engan
1 -mens l$ar = 8;,! mm
1 tebal ++a = 2,8 mm
1 berat = 5,;/ kg"m
1 m-$l$s tam+ang = !5,; (m3
-angga+ san-aran men$m+$ .rntal +a-a tang se(ara t$m+$an se-er.ana
Maka
M ma: = !"8 > l2 = !"8 !00 4,72 = 27/,!25 kg
3
2
;,!5
!0!25,27/ma:
cm
kgcm x
w
M ==σ
= !73/,/3 Kg"(m2 ? 2"2/2; cmkg =σ
B. Perhitungan Lantai Trotoar
- Berat sen-r = 0,2 : ! : ! : 2500
= 500 kg"m
- Betn t$mb$k = 0,2 : ! : ! : 2200
= 440 kg"m
- Berat beban .-$+ = ! : 500
= 500 kg"m
- Berat ar .$jan &5 (m* = 0,05 : !000 : ! : !
= 50 kg"m
- Berat ttal &>*
= !4;0 kg"m
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 3
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Tugas Perencanaan Struktur Baja 2
M$ = @ : > :L2
= @ : !4;0 : !2 = 745 kgm = 7450 m
- = 200 50 @ !2 = !44 mm
#en$langan lanta trtar
k = Mpa x x
x
d b
Mu
45,0!44!0008,0
!07450
2
3
2 ==φ
00!7,0 3085,0
45,02 !!
;,2/2
3085,0
B85,0
2 !!
B85,0 =
−−=
−−=
x
x x
fc
k
fy
fc perlu ρ
005,0 4,!
mn == fy
ρ
005,0mnmn ==→< ρ ρ ρ ρ perlu
J$mla. t$langan lent$r
As = ρ : b : -
= 0,005 : !000 : !44
= 720 mm2
+aka t$langan 8 !2 &As = ;05 mm2*
Kntrl ter.a-a+ ka+astas +elat
C =
As : 'y = 0,85 : '() : a : b
a = b x fc x
fy x As
B85,0
= mm
x x
x 33,;
!0003085,0
;,2/2;05 =
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 4
8/18/2019 TP Baja 2 Fahmi Dan Sandi
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Tugas Perencanaan Struktur Baja 2
( = mm a
;8,!0 85,0
33,;
! ==
β
's = /00
−
c
cd
's = /00 *&;,2/285,72/8 ;8,!0
;8,!0!44 OK Mpa Mpa >=
−
Mn = As'y
−
2
a d
Mn = ;05 : 2/2,; Nm Nmm 2!,33!5!2!,33!5!2!0 2 33,;!44 ==
−
*&45,4 7450
2!,33!5! OK
Mu
Mn ==
Gambar #en$langan Crtar
C. Perencanaan Teknis Pelat Lantai
ata tekns +elat lanta ken-araan
Gambar Kn-s Batas #elat Betn
• Letak +elat +a-a t$m+$an $j$ng,
• #anjang +elat betn, L = 4,7 m
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 5
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Tugas Perencanaan Struktur Baja 2
• Lebar +elat betn, B = 2,75 m
• Cebal +elat betn, ts = 0,20 m
• Cebal la+s +erkerasan, t + = 0,05 m
• ameter t$langan +elat, -t = !/ mm
a* as ss +anjang ter.a-a+ lebar +elat
k = f ! B
L = 8
; : 75,2
7,4 = !,;2
b* Ke'sen re-$ks mmen rm= 0,25
(* #er.t$ngan beban teta+
1 Berat #lat Betn 25 : 0,20 : 4,7 : 2,75 = /4,/3 k
1 Berat As+al 22 : 0,05 : 4,7 : 2,75 = !4,22 k
1 Berat Ar $jan ;,8 : 0,05 : 4,7 : 2,75 = /,33 k
Ctal #- = 85,!8 k
Gambar Beban Mat #elat
as b-ang beban +elat
B
u = 75,2
75,2 = !
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 6
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Tugas Perencanaan Struktur Baja 2
L
v = 7,4
7,4 = !
ar gra'k M #gea$- -+erle. nla ke'sen mmen
mD = 7,8!012
m2 = 3,0!0 12
Mmen lent$r beban mat
Mdl x = rm : #- : &m! 9 0,!5m2*
Mdl x = 0,25 : 85,!8 : &7,8!0-2 + 0,!5 : 3,0!0-2* = !,757 km"m
Mdl y = rm : #- : &m2 9 0,!5m!*
Mdl y = 0,25 : 85,!8 : &3,0!0-2 9 0,!5 : 7,8!0-2* = 0,888 km"m
-* #er.t$ngan beban .-$+
Beban .-$+ ber-asarkan ###JJ !;87
#! = 2 ! : 20 = !0 tn = !00 k
Cngg #enyebaran Beban -a
Gambar #enyebaran Beban -a
. = 0,05 9 &0,2 0,02 -t"2* → -t = 0,!/
. = 0,!5 m
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 7
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Tugas Perencanaan Struktur Baja 2
Kn-s #embebanan E
Gambar Kn-s #embebanan !
$ = 0,5 9 &2 : 0,!5* = 0,8 m
F = 0,3 9 &2 : 0,!5* = 0,/ m
as b-ang beban +lat
B
u = 75,2
8,0 = 0,2;!
L
v = 7,4
/,0 = 0,!28
ar gra'k M #gea$- -+erle.
m! = 2!!0-2
m2 = !4,5!0 -2
Mmen lent$r beban .-$+ kn-s E
Mll !: = rm : P ! : &m! 9 0,!5m2*
Mll !: = 0,25 : !00 : &2!!0-2 9 0,!5 : !4,5!0-2* = 5,7; km"m
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 8
8/18/2019 TP Baja 2 Fahmi Dan Sandi
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Tugas Perencanaan Struktur Baja 2
Mll !y = rm : #! : &m2 9 0,!5m!*
Mll !y = 0,25 : !00 : &!4,5!0 -2
9 0,!5 : 2!!0 -2
* = 4,4! km"m
Kn-s #embebanan EE
Gambar Kn-s #embebanan EE
rmas &*
$ = 2 &$! 9 : * = 2 &0,8 9 &0,!** = !,8 m
F = 0,/ m
as b-ang beban +elat
B
u = 75,2
8,! = 0,/5
L
v = 7,4
/,0 = 0,!28
ar gra'k M #gea$- -+erle. nla ke'sen mmen
m! = !3!0‾²
m2 = !!!0‾²
m! : & ư! 9 x * = !3!0-2 : &0,8 9 &0,!** = !!,7!0 12
m2 : & ư!9 x * = !!!0-2 : &0,8 9 &0!** = ;,;!0 12
rmas &*
- Fahmi Andrian Sya (107011024) - M. Syandi (107011026) 9
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Tugas Perencanaan Struktur Baja 2
$ = 2x = 2: &0,!* = 0,2m
F = 0,/
as b-ang beban +elat
B
u = 75,2
2,0 = 0,07
L
v = 7,4
/,0 = 0,!28
ar gra'k M #gea$- -+erle. nla ke'sen mmen
m! = 2/,5!0-2
m2 = !7,5!0-2
m!x = 2/,5 !0 12 0,! = 2,/ : !012
m2 x = !7,5 !0 12 0,! = !,75 : !012
rmas &* = &* &*
m!= !!,7!0 12