ESFUERZOS EN VIGAS

Vigas GI=R−A−3

- Vigas apoyo simple

- Vigas con voladizo

- Vigas con doble voladizo

- Vigas empotrada

1) Resolver:

V

5

5 – 2 = 3

3 – 2 = 1

1 – 2 = -1

-1 – 2 = -3

-3 – 2 = -5

-5 + 5 = 0

M

0

0 + (1) (5) = 5

5 + (1) (3) = 8

8 + 1 = 9

9 + (1) (-1) = 8

8 + (1) (-3) = 5

5 + (1) (-5) = 0

2) Resolver:

V

7

7 – (2) (4) = -1

-1 – 4 = -5

-5 + 5 = 0

M

0

0+(3.5 )(7)2

=12.25

12.25+(0.5)(−1)

2=12

12+(2 ) (−1 )=10

10 + (2) (-5) = 0

3) Resolver:

V

4.8

4.8 – (2) (4) = -3.2

-3.2 – 4 = -7.2

-7.2 + 7.2 = 0

M

0

0+(3.5 )(7)2

=12.25

12.25+(0.5)(−1)

2=12

12+(2 ) (−1 )=10

10 + (2) (-5) = 0

4) Resolver:

[∑M A=0 ]

−2 (3 )−1 (3 )+2.4 (5.2 )−5.4 (1.2 )−By (4)=0

By=0.75

[∑M B=0 ]

−5.4 (1.2 )+2.4 (0.8 )+1 (1 )+8 (4 )−2 (3 )−Ay (4)=0

Ay=8.25

Lado I

[∑MC=0 ]

8 (2 )+2 (3 )+Ax (6 )−8.25 (2 )=0

Ax=−0−92

Lado II

[∑MC=0 ]

−1 (1 )−2.4 (0.8 )+5.4 (4.8 )−Bx (6 )=0

Bx=4.8