FORMA CANONICA DE JORDAN

1. Calcular la forma canonica de Jordan y la matriz depaso para las siguientes matrices:

(a) A =

0 1 1 00 1 0 11 1 0 00 2 0 1

(b) A =

6 9 5 47 13 8 78 17 11 81 2 1 3

(c) A =

3 1 1 10 2 0 11 1 1 00 0 0 2

(d) A =

2 0 0 25 2 2 23 1 0 31 0 0 0

(e) A =

1 2 30 1 11 1 2

(f) A =

1 3 5 2 00 1 3 1 00 1 2 0 00 0 1 2 00 1 3 2 1

1

(g) A =

6 0 0 30 6 0 00 3 6 00 0 0 6

(h) A =

2 1 1 22 1 1 01 0 0 11 2 0 1

(i) A =

3 1 0 19 5 0 93 2 1 34 3 0 6

(j) A =

0 1 1 1 12 3 1 1 12 1 3 1 13 3 0 3 16 9 6 7 5

2