sin x=∑n=1

∞ (−1)n−1 x2n−1

(2n−1) !

cos x=∑n=0

∞ (−1 )n x2n

(2n )!

∑k=1

n

ark−1= a (1−r n )(1−r )

Ka=¿¿

(P+ an2

V 2 ) (V−bn )=nRT

r=n2 h2

me kZe2=n2

a0Z

En=−RH( 1n2 )=−2.178×10−18

n2joule

∫cos (ax )dx=1aln|tan( ax2 + π

4 )|+c

∫ xndx= xn+1

n+1, (n≠−1 )

limn→e

f (x)g(x )

=limx→e

f ' (x)g '(x )

a=∑ y−b∑ xn

b=n∑ ( xy )−(∑ x ) (∑ y )

n∑ x2−(∑ x)2