Report - giri/pdfs/EE4140-2020/ee4140-tute4-solutions.pdf3 = E I(n 3) z(n) z(n 1) = 0 0:5 ˙2 I R zz 1 = 0:5522 0:1886 0:1886 0:5522 J 0 = ˙2 I Tp 0 R zz 1p 0 = 0:2720 J 1 = 0:1104 J 2 = 0:1145

Select PornographicDefamatoryIllegal/UnlawfulSpamOther Terms Of Service ViolationFile a copyright complaint

Please pass captcha verification before submit form