Proyecto de Aula # 1

f(x)=x2+3x-10

v ca 1b 3c -10

1mer paso

0=x2+3x-10

x1−2=−3±√32−4 (1)(−10)

2(1)

x1−2=−3±√9+40

2

x1−2=−3±√49

2

x1−2=−3±72

x1=−3+72

=42

= 2 A= (2,0)

x2=−3−72

=- 102

= -5 B= (-5,0)

2do paso

X= -b2a

= - 32

f(- 32)=(-

32 ¿2 +3(-

32 ) -10 =

94 -

92 -10 =

9−18−104 =

494

V= (- 32, 494

)

Grafique la Función Cuadrática f(x)=x2+3x-10

3er paso

F(0)=(0)2+3(0) -10 = -10 (0, -10)

Proyecto de Aula # 2

f(x)=x2+6x-16

v ca 1b 6c -16

1mer paso

0=x2+6x-16

x1−2=−6±√62−4 (1)(−16)

2(1)

x1−2=−6±√36+64

2

x1−2=−6±√100

2

x1−2=−6±102

x1=−6+102

=42

= 2 A= (2, 0)

x2=−6−102

=- 162

= -8 B= (-8, 0)

2do Paso

X= -b2a

= - 62

= -3

f(-3)=(-3 ¿2 +6(-3) -16 = 9 - 18 -16 = -25

Grafique la Función Cuadrática f(x)=x2+6x-16 si -2≤x<2

V= (- 3 ,-25)

3er paso

F(0)=(0)2+6(0) -16 = -16 = (0, -16)

Proyecto de Aula # 3

f(x)=x2

f(-3)= (-3¿2= 9 (-3,9)

f(-2)= (-2¿2= 4 (-2,4)

f(-1)= (-1¿2= 1 (-1,1)

f(0)= (0¿2= 0 (0,0)

f(1)= (1¿2= 1 (1,1)

f(2)= (2¿2= 4 (2,4)

f(3)= (3¿2= 9 (3,9)

f(x)=x2+4

f(-3)= (-3¿2+4= 9+4 (-3,13)

f(-2)= (-2¿2+4= 4+4 (-2,8)

f(-1)= (-1¿2+4= 1+4 (-1,5)

f(0)= (0¿2+4= 4 (0,4)

f(1)= (1¿2+4= 1 +4(1,5)

f(2)= (2¿2+4= 4+4(2,8)

Grafique la Función Cuadrática f(x)=x2; f(x)=x2+4; f(x)=x2-4 si X={-3,-2,-1,0,1,2,3}

f(3)= (3¿2+4= 9+4 (3,13)

f(x)=x2-4

f(-3)= (-3¿2-4= 9-4 (-3,5)

f(-2)= (-2¿2-4= 4-4 (-2,0)

f(-1)= (-1¿2-4= 1-4 (-1,-3)

f(0)= (0¿2-4= -4 (0,-4)

f(1)= (1¿2-4= 1 -4(1,-3)

f(2)= (2¿2-4= 4-4(2,0)

f(3)= (3¿2-4= 9-4 (3,-5)

Proyecto de Aula # 4

f(x)=(x−3)2

(x−3)2=0

√(x−3)2= √0

X-3=0

X=3 =(3,0)

F(0)=(0−3)2 =(−3)2 = 9 = (0,9)

Grafique la Función Cuadrática f(x)=(x-3¿2